Q16 1 x yz 1 y zx 1 z xy
= 1 x x2 1 y y2 1 z z2
= (x-y)(y-z)(z-x)
Solution
,
1 | x | yz |
1 | y | zx |
1 | z | xy |
1 | x | x2 |
1 | y | y2 |
1 | z | z2 |