(iii) In the adjoining figure, AC is a diameter of the circle. AP = 3cm and PB = 4cm and QP ⊥ AB. If the area of ▵APQ is 18 cm² , then the area of shaded portion QPBC is:

(a) 32 cm²
(b) 49 cm²
(c) 80 cm²
(d) 98 cm²

Solution