Show that the time required for 99.9% completion in a first order reaction is 10 times of half-life (t1/2) of the reaction [log 2 = 0.3010, log 10 = 1].
Solution
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Show that the time required for 99.9% completion in a first order reaction is 10 times of half-life (t1/2) of the reaction [log 2 = 0.3010, log 10 = 1].
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