(ii) If 𝑥 2 + 𝑘𝑥 + 6 = (𝑥 − 2 )(𝑥 − 3) for all values of x, then the value of k is:
(a) – 5
(b) – 3
(c) – 2
(d) 5
Solution
(ii) If 𝑥 2 + 𝑘𝑥 + 6 = (𝑥 − 2 )(𝑥 − 3) for all values of x, then the value of k is: