Class 10 ICSE Trigonometric

This study guide is your ultimate resource for mastering ICSE Class 10 Mathematics. It offers clear explanations of key concepts, ample practice problems, and effective strategies for tackling questions with confidence. With a focus on exam preparation, this guide provides the tools you need to excel in your ICSE Mathematics exam.

class 10 Trigonometric Chapter Test

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Trigonometric  

Q1 (i) If θ is an acute angle and cosec θ = √5,find the value of cot θ- cos θ
(ii) If θ is an acute angle and tan θ =8/15,find the value of sec θ + cosec θ


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Q2 Evaluate the following:
(i) 2 x (
cos220° + cos2 70° / sin225° + sin265°
)-tan 45° + tan 13° tan 23° tan 30° tan 67° tan 77°
(ii)
sin222° + sin2 68° / cos222° + cos268° + sin2 63° + cos 63° sin 27°


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Q3 If 4/3(sec2 59° - cot2 31°)- 2/3 sin 90° + 3 tan2 56° tan2 34°= x/3,find the value of x


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Q4 (i)
cos A / 1- sinA
+
cos A / 1 + sinA
=2 sec A
(ii)
cos A / cosec A + 1
+
cos A / cosec A -1
=2 tan A
(iii)
(cos θ - sin θ)(1 + tan θ) / 2 cos2θ -1
= secθ


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Q5 (i) sin2 θ + cos4 θ= cos2 θ + sin4 θ
(ii)
cot θ / cosec θ +1
+
cosec θ +1 / cot θ
= 2 secθ


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Q6 (i) sec4A(1 - sin4A)-2tan2A=1
(ii)
1 / sin A + cos A +1
+ = sec A + cosec A


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Q7 (i)
sin3θ + cos3θ / sin θ + cos θ
+ sinθ cosθ =1
(ii) (sec A - tan A)2(1 + sin A) =1- sin A


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Q8 (i)
cos A / 1- tan A
-
sin2 A / cos A - sin A
= sin A + cos A
(ii) (sec A - cosec A)(1 + tan A + cot A)= tan A sec A - cot A cosec A
(iii)
tan2θ / tan2θ-1
+
cosec2θ / sec2θ-cosec2θ=
1 / sin2θ-cos2θ




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Q9
sin A + cos A / sin A - cos A
+
sin A - cos A / sin A + cos A
=
1 / sin2 A - cos2 A
=
2 / 1 - 2cos2 A
=
2 sec2A / tan2 A-1


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Q10 2 (sin6θ + cos6θ) -3(sin4θ + cos4θ) + 1=0


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Q11 If cot θ + cos θ =m and cot θ - cosθ=n,then prove that (m2-n2)2 = 16 mn


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Q12 when 0° < θ < 90°,solve the following equations:
(i) 2 cos2θ + sin θ -2 =0
(ii) 3 cosθ=2 sin2 θ
(iii) sec2θ -2 tanθ=0
(iv) tan2 θ = 3(sec θ -1)


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