(i) f(x) = x³ in [-2, 2]
(i1) f(x) = (x - 1)² +3 in [-3, 1]
(iii) f(x)= 4x - 1/2 x² in [-2 , 9/2]
(iv) f(x) = 2x³ 15x² + 36x + 1 on the interval [1, 5]
(v)f(x)= -x + 3 in [-2, 2.5]
(vi) f(x) = 3x⁴ -8x³+ 12x² - 48x +25 in [0, 3]
(vii) f(x) = x + sinx in [0, 2 π]
(viii) f(x) = sin x + cos in [0, π]
(ix) f(x) = 3 + |x + 1| in [-2, 3].

Solution

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